Ady1 | 13/10/2015 11:49:43 |
![]() 6137 forum posts 893 photos | Even the elusive 59tpi becomes possible on a crappy gearset with an error of 0.01
58.996361 n[25.000000] n[25.000000] n[60.000000] n[55.000000] n[65.000000] n[65.000000]
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Bazyle | 13/10/2015 12:11:30 |
![]() 6956 forum posts 229 photos | Well I for one have no idea what you're on about. Got lost half a million decimal points ago. |
John Stevenson | 13/10/2015 13:14:41 |
![]() 5068 forum posts 3 photos | Your maths is way out.
58.996361 n[55.000000] n[25.000000] n[65.000000] n[25.000000] n[60.000000] n[65.000000]
No way you can reverse the last two gears and still have the same ratio |
Neil Wyatt | 13/10/2015 13:31:19 |
![]() 19226 forum posts 749 photos 86 articles | Problem is here: Also some have the same issue with teh first two gears eg 59-23, 50-59, 62-82 can't be the same as 23-59, 50-59, 62-82 can it? ----------------------------------- 59 23-50 59-62 82 23 59-50 59-62 82 first: (23/50)*59=27.14 (59/62)*27.14=25.82677 82/25.82677=3.17499 3.17499*8tpi=25.3999tpi second: (59/50)*23=27.14 (59/62)*27.14=25.82677 82/25.82677=3.17499 3.17499*8=25.3999tpi It all seems ok to me, (only playing about though)
It looks to me like you are not calculating the ratios correctly (you have got some of the ratios upside down). I get the two setups to give completely different ratios; 59 23-50 59-62 82 (59*50*62)/(23*59*82) = 1.6437 23 59-50 59-62 82 (23*50*62)/(59*59*82) = 0.2498 Neil Edited By Neil Wyatt on 13/10/2015 13:33:25 |
Ian P | 13/10/2015 13:40:08 |
![]() 2747 forum posts 123 photos | Well, I've doubled the result and taken away the first number I thought of, but I still dont get the same answer as you do in the third line down. Ian P |
Ady1 | 13/10/2015 14:09:49 |
![]() 6137 forum posts 893 photos | I've probbly still got the gearsets printout the wrong way round, the maths do work though... once you jumble it about to the right way round...
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John Stevenson | 13/10/2015 14:10:35 |
![]() 5068 forum posts 3 photos | You need to add the inverse of Pi. |
Ady1 | 13/10/2015 14:20:58 |
![]() 6137 forum posts 893 photos | I'll try one: 58.996361 n[25.000000] n[25.000000] n[60.000000] n[55.000000] n[65.000000] n[65.000000] 25 * (25/60) =10.416667 10.416667*(55/65)=8.81410 65 / 8.81410=7.374545 8tpi * 7.374545 = 58.996 TA-DAAAAA! I always knew I was a genius... the compound gears are 60in/25out and 65in/55out
Edited By Ady1 on 13/10/2015 14:29:09 |
Ian P | 13/10/2015 14:29:00 |
![]() 2747 forum posts 123 photos | Posted by John Stevenson on 13/10/2015 14:10:35:
You need to add the inverse of Pi. Makes much more sense with your suggested correction John. I was beginning to think the mathematics of screwcutting was being played out in Mornington Cresent. Ian P
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Michael Gilligan | 13/10/2015 14:29:14 |
![]() 23121 forum posts 1360 photos | Posted by Ady1 on 13/10/2015 14:20:58:
the compound gears are 60in/25out and 65in/55out . So ... one of your two answers is correct What's the relevance of the other one ? MichaelG. [still bewildered] |
Ady1 | 13/10/2015 14:31:52 |
![]() 6137 forum posts 893 photos | Einsteins maths teacher said he was rubbish at maths too, so I'm in good company So ... one of your two answers is correct What's the relevance of the other one ? It depends which dimension you're in Edited By Ady1 on 13/10/2015 14:34:42 |
Ady1 | 13/10/2015 14:45:54 |
![]() 6137 forum posts 893 photos | 58.996361 n[55.000000] n[25.000000] n[65.000000] n[25.000000] n[60.000000] n[65.000000] 58.996361 n[55.000000] n[25.000000] n[65.000000] n[25.000000] n[65.000000] n[60.000000] No way you can reverse the last two gears and still have the same ratio
Yes you can, (the different compound output is turning a different size idler gear on the leadscrew so in certain cases gears can be swapped) 55*(25/65)=21.1538 21.1538 * (25/60)=8.8141 65 / 8.8141=7.374545 7.374545 * 8=58.996tpi ========================
55*(25/65)=21.1538 (25/65)*21.1538=8.1360 60 / 8.1360=7.3745 7.3745 * 8tpi=58.996tpi ======================= Edited By Ady1 on 13/10/2015 15:07:56 |
John Stevenson | 13/10/2015 17:37:03 |
![]() 5068 forum posts 3 photos | Well at least write the formulae in the correct sequence.
Those two above are identical in sequence and how are we to know what order to take them in.
Einstein might have been rubbish at maths but you are rubbish at logic. Edited By John Stevenson on 13/10/2015 17:37:30 |
Michael Gilligan | 13/10/2015 22:17:14 |
![]() 23121 forum posts 1360 photos |
Edited By Michael Gilligan on 13/10/2015 22:18:11 |
bodge | 13/10/2015 23:18:17 |
186 forum posts 3 photos | Afraid i dont know how to do the link things like Michael G [ and others ], some might like this though. Pagagnini - Pachelbel"s Canon in D , You tube. oops way of topic ,sorry Ady. bodge |
Ady1 | 16/10/2015 16:29:02 |
![]() 6137 forum posts 893 photos | Posted by John Stevenson on 13/10/2015 17:37:03:
Well at least write the formulae in the correct sequence. Einstein might have been rubbish at maths but you are rubbish at logic. It gets worse... I wanted to drill holes or cut teeth for weird tooth numbers with limited gearsets using the banjo/headstock as a division tool and I may have cracked it A 59 tooth gear with 0.0002 error Gearset 20 25 30 35 40 45 46 50 55 60 63 65 The first gear, 20, is irrelevant, all that matters is if it's moved 59 times and the compund set moves the final gear, (which in case one is a 46tooth) 59 times AND completes a proper 360 degree revolution then we have a winnah As usual my outputs are jumbled up 0.999856 n[20.000000] n[30.000000] n[46.000000] n[55.000000] n[46.000000] n[46.000000] Soooo... the 20 is irrelevant, then 46in 30out and 46in 55out to a final spindle cog of 46 59 clicks on the detente is (using the 20 or anything you want as an idler) (59/46)*30= 38.478 clicks (38.478/46)*55=46.0066 clicks on a 46.0000 toothed final gear
Full results below (edited to two gearsets) 0.999856 n[20.000000] n[30.000000] n[46.000000] n[55.000000] n[46.000000] n[46.000000] Might be wrong of course but it's looking good so far
Edited By Ady1 on 16/10/2015 16:43:22 |
John Stevenson | 16/10/2015 17:07:23 |
![]() 5068 forum posts 3 photos | How can the PRIME driver be irrelevant ??
Idlers yes, drivers and driven, no |
Ady1 | 16/10/2015 17:33:31 |
![]() 6137 forum posts 893 photos | It's a 20 pretending to be a 59 It's all kosher, honest guv, on my life. My initial interest was for the Westbury dividing head which fits onto the milling slide/saddle of your lathe The first cog is only an idler in this case, then 2X compound gears and the final spindle gear Can't remember which book it was in... Hemingway do a kit edit: If it is relevant, then swap the 20 for a 46 and do 59 divisions edit2 It wasn't westbury, it was the sparey one I was thinking of, in "the amateurs lathe" Edited By Ady1 on 16/10/2015 17:54:12 |
John Stevenson | 16/10/2015 17:43:55 |
![]() 5068 forum posts 3 photos | I think you lost me when you wrote the third word in your first post.................................. |
Ajohnw | 16/10/2015 17:51:42 |
3631 forum posts 160 photos | Posted by bodge on 13/10/2015 23:18:17:
Afraid i dont know how to do the link things like Michael G [ and others ], some might like this though. Pagagnini - Pachelbel"s Canon in D , You tube. oops way of topic ,sorry Ady. bodge There are these icons above the area where replies etc are typed out and lo hover the cursor over them and what they do pops up. Click one if it's the right one and it actually allows you to do it, links can be pasted in. John - |
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