Neil Wyatt | 01/07/2022 11:27:32 |
![]() 19226 forum posts 749 photos 86 articles | I have a kitchen scale, an old style pan balance. But I only have the 2lb weight! I have loads of scrap to make weights from, but no access to another weighing device. What's the quickest way to make a set of weights that will weigh anything from 1 ounce to 4lbs?
Neil Edited By Neil Wyatt on 01/07/2022 11:27:55 |
JasonB | 01/07/2022 11:33:17 |
![]() 25215 forum posts 3105 photos 1 articles | Isn't it about time you went metric The 4lbs one is easy, weigh two lots of scrap so they measure 2lbs each and then combine the two. |
David Noble | 01/07/2022 11:38:21 |
![]() 402 forum posts 37 photos | Weigh 2lbs of scrap then divide it so that the two halves balance that will give you two 1lb weights. Then just do the same with the 1lb weight to give you 8oz then 4oz etc. Much more difficult in metric!
David Edited By David Noble on 01/07/2022 11:40:16 |
Hopper | 01/07/2022 11:43:28 |
![]() 7881 forum posts 397 photos | Get a bunch of coins of the same denomination and see how many it takes to equal your two pound weight then divide the number of coins into 2LB and use that to calculate ounce weights? |
JasonB | 01/07/2022 11:46:18 |
![]() 25215 forum posts 3105 photos 1 articles | You don't say what form the scrap is in or if you are able to use other tools. If it is lengths of bar and you have tools then keep cutting bits off a bar until it weighs 2lbs. Then measure that length of bar and simply cut others a proportional length to get the required weights. |
duncan webster | 01/07/2022 11:54:59 |
5307 forum posts 83 photos | Density of mild steel is 0.283 lbm/cu.in. All you need now is a calculator. |
Andrew Johnston | 01/07/2022 12:13:44 |
![]() 7061 forum posts 719 photos | The problem is incompletely specified, what about weighing 1.5 ounces? Andrew |
roy entwistle | 01/07/2022 12:26:41 |
1716 forum posts | Andrew He hasn't asked about 1/1/2 oz. but all he's got to do is halve the 1oz Roy |
Andrew Johnston | 01/07/2022 12:57:18 |
![]() 7061 forum posts 719 photos | Roy, I'm afraid you missed my point. The implication is that the set of new weights needs to be able to weigh from 1 ounce to 4 pounds in 1 ounce steps. But that is not explicitly stated. Instead it says anything from 1 ounce to 4 lbs, in which case 1.5 ounces is valid, as would be 1.25 ounces or 1.75 ounces, in fact an infinite number of weights. Andrew |
Nick Clarke 3 | 01/07/2022 12:59:09 |
![]() 1607 forum posts 69 photos | This is an engineer's problem. The customer services's answer would be that you are trying to weigh things weighing the wrong amount. |
JasonB | 01/07/2022 13:02:52 |
![]() 25215 forum posts 3105 photos 1 articles | It's obviously a problem that has been weighing on Neil's mind for some time. Probably better to weigh in the scrap and buy a set of digital scales with the money then all increments will be covered. |
SillyOldDuffer | 01/07/2022 13:03:05 |
10668 forum posts 2415 photos | Making my head hurt, if I've read the exam question correctly. My bold: What's the quickest way to make a set of weights that will weigh anything from 1 ounce to 4lbs? I think another way of wording the question is: 'what's the smallest number of individual weights that can balance any weight between 1oz and 4lbs in 1oz increments?' If it helps, and I'm not sure it does, it might be possible to reduce the total number weights to be made by adding one or more of them to the unknown side, as in 3oz unknown + 1 oz standard balances a 4 oz standard, potentially eliminating the need for a 2oz. I don't think this is as simple as just dividing or multiplying by two because that way means a lot of individual weights are needed to measure anything between one ounce and 4 pounds in one ounce increments. For example solving the problem by making 64 one ounce weights breaks the quickest way rule. The process is easy but a lot of them have to be made, which takes time. The way I read it, metric versus Imperial is a red-herring! Dave
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JasonB | 01/07/2022 13:07:09 |
![]() 25215 forum posts 3105 photos 1 articles | You don't need lots of weights Dave, they were never supplied with 64 1oz weights. You just juggle the combinations eg 5oz would not need 5 individual 1oz weights just a 1oz and a 4oz Edited By JasonB on 01/07/2022 13:07:32 |
SillyOldDuffer | 01/07/2022 13:33:14 |
10668 forum posts 2415 photos | Posted by JasonB on 01/07/2022 13:07:09:
You don't need lots of weights Dave, they were never supplied with 64 1oz weights. You just juggle the combinations eg 5oz would not need 5 individual 1oz weights just a 1oz and a 4oz ... My daft example was meant to demonstrate why at least one simple answer is off course, not as a serious suggestion! Agreed you have to juggle combinations, but what's the minimum number of weights needed to balance an unknown in the range 1 to 64 ounces in 1 oz steps, and what are their values? In a variant of the question found on the web, any value between 1 and 40 can be balanced with just 4 weights: 1, 3, 9, and 27. Dave
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Nick Clarke 3 | 01/07/2022 13:37:14 |
![]() 1607 forum posts 69 photos | While one always applauds recycling - looking at a set of 8-4-2-1-1/2oz brass weights on the 'bay I think I would save the scrap for the next project. |
JasonB | 01/07/2022 13:38:57 |
![]() 25215 forum posts 3105 photos 1 articles | 1, 2, 4, 8, 16 (1Ibs) and 32 twice (2 x 2lbs) to get from 1-64 inclusive. You could also do it with 32 and 64oz weights rather than 2 x 32 but that would use up more of Neil's scrap How would you weigh say 20 with a combination of 1, 3, 9 and 27?
Edited By JasonB on 01/07/2022 13:43:16 |
V8Eng | 01/07/2022 13:44:06 |
1826 forum posts 1 photos | I would try the lazy way first and trawl the local charity shops or eBay but that’s just me! |
Thor 🇳🇴 | 01/07/2022 13:47:37 |
![]() 1766 forum posts 46 photos | Several good answers, Neil, if you have access to something to measure volume of liquid, you could use a certain volume of water to get the weights you need (you would of course, have to tare the container). Handy calculator here. Thor Edited By Thor 🇳🇴 on 01/07/2022 13:51:39 |
Mike Poole | 01/07/2022 13:53:54 |
![]() 3676 forum posts 82 photos | Posted by JasonB on 01/07/2022 13:38:57:
1, 2, 4, 8, 16 (1Ibs) and 32 twice (2 x 2lbs) to get from 1-64 inclusive. You could also do it with 32 and 64oz weights rather than 2 x 32 but that would use up more of Neil's scrap How would you weigh say 20 with a combination of 1, 3, 9 and 27?
Edited By JasonB on 01/07/2022 13:43:16 I would put the 27 and 3 on one side and the 9 and 1 on the other, add the item to be weighed until balanced. Mike |
Paul Lousick | 01/07/2022 14:09:47 |
2276 forum posts 801 photos | If you don't have a weigh scale, bathroom scale, etc, you could use a a liquid measure of water.
The imperial fluid ounce is the volume of 1 avoirdupois ounce of water at 62° F., so you could use a liquid measure of water to determine the size of the steel "weight" with a simple balance.
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