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Simple Quiz... Missing Weight

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Neil Wyatt01/07/2022 11:27:32
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I have a kitchen scale, an old style pan balance.

But I only have the 2lb weight!

I have loads of scrap to make weights from, but no access to another weighing device.

What's the quickest way to make a set of weights that will weigh anything from 1 ounce to 4lbs?

 

Neil

Edited By Neil Wyatt on 01/07/2022 11:27:55

JasonB01/07/2022 11:33:17
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Isn't it about time you went metricsmile p

The 4lbs one is easy, weigh two lots of scrap so they measure 2lbs each and then combine the two.

David Noble01/07/2022 11:38:21
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Weigh 2lbs of scrap then divide it so that the two halves balance that will give you two 1lb weights. Then just do the same with the 1lb weight to give you 8oz then 4oz etc.

Much more difficult in metric!

 

David

Edited By David Noble on 01/07/2022 11:40:16

Hopper01/07/2022 11:43:28
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Get a bunch of coins of the same denomination and see how many it takes to equal your two pound weight then divide the number of coins into 2LB and use that to calculate ounce weights?

JasonB01/07/2022 11:46:18
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You don't say what form the scrap is in or if you are able to use other tools. If it is lengths of bar and you have tools then keep cutting bits off a bar until it weighs 2lbs. Then measure that length of bar and simply cut others a proportional length to get the required weights.

duncan webster01/07/2022 11:54:59
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Density of mild steel is 0.283 lbm/cu.in. All you need now is a calculator.

Andrew Johnston01/07/2022 12:13:44
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The problem is incompletely specified, what about weighing 1.5 ounces?

Andrew

roy entwistle01/07/2022 12:26:41
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Andrew He hasn't asked about 1/1/2 oz. but all he's got to do is halve the 1oz

Roy

Andrew Johnston01/07/2022 12:57:18
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Roy, I'm afraid you missed my point. The implication is that the set of new weights needs to be able to weigh from 1 ounce to 4 pounds in 1 ounce steps. But that is not explicitly stated. Instead it says anything from 1 ounce to 4 lbs, in which case 1.5 ounces is valid, as would be 1.25 ounces or 1.75 ounces, in fact an infinite number of weights.

Andrew

Nick Clarke 301/07/2022 12:59:09
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This is an engineer's problem. The customer services's answer would be that you are trying to weigh things weighing the wrong amount.wink 2

JasonB01/07/2022 13:02:52
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It's obviously a problem that has been weighing on Neil's mind for some time. Probably better to weigh in the scrap and buy a set of digital scales with the money then all increments will be covered.

SillyOldDuffer01/07/2022 13:03:05
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Making my head hurt, if I've read the exam question correctly.

My bold: What's the quickest way to make a set of weights that will weigh anything from 1 ounce to 4lbs?

I think another way of wording the question is: 'what's the smallest number of individual weights that can balance any weight between 1oz and 4lbs in 1oz increments?' If it helps, and I'm not sure it does, it might be possible to reduce the total number weights to be made by adding one or more of them to the unknown side, as in 3oz unknown + 1 oz standard balances a 4 oz standard, potentially eliminating the need for a 2oz.

I don't think this is as simple as just dividing or multiplying by two because that way means a lot of individual weights are needed to measure anything between one ounce and 4 pounds in one ounce increments. For example solving the problem by making 64 one ounce weights breaks the quickest way rule. The process is easy but a lot of them have to be made, which takes time.

The way I read it, metric versus Imperial is a red-herring!

Dave

JasonB01/07/2022 13:07:09
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You don't need lots of weights Dave, they were never supplied with 64 1oz weights. You just juggle the combinations eg 5oz would not need 5 individual 1oz weights just a 1oz and a 4oz

Edited By JasonB on 01/07/2022 13:07:32

SillyOldDuffer01/07/2022 13:33:14
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Posted by JasonB on 01/07/2022 13:07:09:

You don't need lots of weights Dave, they were never supplied with 64 1oz weights. You just juggle the combinations eg 5oz would not need 5 individual 1oz weights just a 1oz and a 4oz

...

My daft example was meant to demonstrate why at least one simple answer is off course, not as a serious suggestion!

Agreed you have to juggle combinations, but what's the minimum number of weights needed to balance an unknown in the range 1 to 64 ounces in 1 oz steps, and what are their values?

In a variant of the question found on the web, any value between 1 and 40 can be balanced with just 4 weights: 1, 3, 9, and 27.

Dave

Nick Clarke 301/07/2022 13:37:14
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While one always applauds recycling - looking at a set of 8-4-2-1-1/2oz brass weights on the 'bay I think I would save the scrap for the next project.

JasonB01/07/2022 13:38:57
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1, 2, 4, 8, 16 (1Ibs) and 32 twice (2 x 2lbs) to get from 1-64 inclusive. You could also do it with 32 and 64oz weights rather than 2 x 32 but that would use up more of Neil's scrap

How would you weigh say 20 with a combination of 1, 3, 9 and 27?

 

Edited By JasonB on 01/07/2022 13:43:16

V8Eng01/07/2022 13:44:06
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I would try the lazy way first and trawl the local charity shops or eBay but that’s just me!

Thor 🇳🇴01/07/2022 13:47:37
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Several good answers, Neil, if you have access to something to measure volume of liquid, you could use a certain volume of water to get the weights you need (you would of course, have to tare the container). Handy calculator here.

Thor
 

Edited By Thor 🇳🇴 on 01/07/2022 13:51:39

Mike Poole01/07/2022 13:53:54
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Posted by JasonB on 01/07/2022 13:38:57:

1, 2, 4, 8, 16 (1Ibs) and 32 twice (2 x 2lbs) to get from 1-64 inclusive. You could also do it with 32 and 64oz weights rather than 2 x 32 but that would use up more of Neil's scrap

How would you weigh say 20 with a combination of 1, 3, 9 and 27?

Edited By JasonB on 01/07/2022 13:43:16

I would put the 27 and 3 on one side and the 9 and 1 on the other, add the item to be weighed until balanced.

Mike

Paul Lousick01/07/2022 14:09:47
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If you don't have a weigh scale, bathroom scale, etc, you could use a a liquid measure of water.
The imperial fluid ounce is the volume of 1 avoirdupois ounce of water at 62° F., so you could use a liquid measure of water to determine the size of the steel "weight" with a simple balance.

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