Sharing information about model turbines
Martin Johnson 1 | 13/03/2019 16:53:46 |
320 forum posts 1 photos | Thanks for making me think, chaps. You are right for constant momentum, but greater mass flow, the TORQUE would remain constant for a given design of blades, but at the same time the optimum running speed would fall in the ratio of the mass flow increase (same as velocity decrease). Hence power falls as the ratio of mass flow increase or velocity decrease. All assuming motive and entrained fluids of identical density. BUT earlier in this thread TG is reporting a blade speed to fluid speed ratio of 0.022 - way down on where it should be for a two velocity staged machine. AND even if he can get the running speed up to where it should be, how long will the bearings stand up to it? Or, indeed, how long will the blades stay attached to the hub? AND what losses would there be in a wee gearbox to reduce the speed to something manageable? So, the question remains for tiny turbines, would an ejector lose more than it gains? For all that, I am in awe of the tiny rotor and blade cutting that TG is undertaking. Also, the methodical way it is being thought through. Keep the reports on progress coming, please. Martin |
Turbine Guy | 13/03/2019 18:54:24 |
541 forum posts 578 photos | The following is a similar analysis as in the 13/03/2019 posts for the GH ½ B model jet pump Air inlet pressure of 0 psig Air inlet temperature of 70 F Air inlet enthalpy of 126.7 btu/lb Steam pressure of 120 psig, Steam temperature is 351 F Steam enthalpy is 1192 btu/lb. Suction capacity is approximately 54 SCFM. ½ B Capacity factor is 0.030. 1½ model steam consumption is 390 lb/hr ½ B model steam consumption is 11.7 lb/hr ½ B air pumped = 1.6 SCFM ½ B mass flow of air is 7.2 lb/hr Discharge pressure is 12 psig, Discharge temperature is 300 F Discharge enthalpy is 1192 btu/lb Discharge mass flow is 18.9 lb/hr. The mixture isentropic enthalpy drop to a pressure of 0 psig is 1192 – 1144 = 48 btu/lb. The exit velocity from a nozzle with this enthalpy drop is 1550 ft/sec. The energy of the mixture is 48 btu/lb x 18.9 lb/hr = 907 btu/hr The isentropic enthalpy drop from the 120 psig and 351 F to a pressure of 0 psig is 1192 – 1045 = 147 btu/lbm. The exit velocity from a nozzle with this enthalpy drop is 2,713 ft/sec. The energy of the steam is 147 btu/lb x 11.7 lb/hr = 1720 btu/hr. This model jet pump was designed to move higher flows with less steam and works better. The extra mass flow and lower velocity increases the nozzle size or quantity which can make a substantial difference on small turbines. I'll read the discussions on momentum exchange and respond. Edited By Turbine Guy on 13/03/2019 19:00:55 |
Turbine Guy | 13/03/2019 23:13:27 |
541 forum posts 578 photos | Martin, The equation I use for the power of an ideal impulse turbine might help show the effect of changes.
Increasing the mass flow or spouting velocity without any other changes will always increase the power. Increasing the rotor speed up to a maximum of ½ the spouting velocity will also increase power in the ideal case but rotational losses have to be dealt with in real turbines. What I found in the last post is starting to convince me using an ejector might actually help. I'm going to look at this a little more. I appreciate you comments on my methodical approach and machining the tiny blades. I enjoy the engineering and design as much as making the models. Because of the cost of the tools required and my limited machining skills, It will be a while before I try making the model Terry turbine. I have an improved version of the open pocket rotor I plan to make next. |
Turbine Guy | 14/03/2019 18:14:21 |
541 forum posts 578 photos | I finally have enough information to give an indication of how effective using an ejector could be for small turbines. A Penberthy GL ½ A ejector has the following performance. With this information I can use the following chart to estimate the performance with and without the ejector. This chart estimates the maximum performance for the given specific speed Ns and specific diameter Ds. It is intended to be used by first deciding the speed you would like to run and then calculating the specific speed Ns. You then use Ns to find the Ds that gives the best efficiency. You can then find the optimum rotor diameter from the Ds. I am using a turbine speed of 10,000 rpm for this comparison. For the ejector, Q3 = 0.095 ft^3/sec, Had = 24,896 ft-lb/lb, and Ns = 1.56 Without the ejector, Q3 = 0.055 ft^3/sec, Had = 108,142 ft-lb/lb, and Ns = 0.39 Using the ejector, the efficiency of the turbine is double that of the turbine without the ejector. The ejector definitely improves the transfer of energy in the turbine. However, the discharge mixture from the ejector has so much less energy that the power ends up almost the same. |
Turbine Guy | 15/03/2019 12:05:30 |
541 forum posts 578 photos | The heavy solid lines in the chart of the preceding post are for axial turbines. The dashed lines are for Terry turbines. The thin solid lines are for Drag turbines. The drag turbines are like turbine pumps. The blades circulate the flow in a way that increases the drag force on the rotor. The units for the volume flow are ft*3/sec and for the gas density lb/ft^3. Edited By Turbine Guy on 15/03/2019 12:08:55 |
Turbine Guy | 26/03/2019 19:13:22 |
541 forum posts 578 photos | In the post of 08/03/2019 I showed a revised rotor and stated that it could get a rotor velocity coefficient of up to 1.64 times that of my existing turbine rotor. I built this rotor almost as shown on the drawing attached to the 08/03/2019 post. The following photo shows the new rotor (aluminum) next to the original rotor (brass) I tested this rotor with the same air pressure and flow used in the test of my original rotor that had a maximum speed of 17,000 rpm. The maximum speed with the new rotor was 18,250 rpm. The required power of the EP2508 propeller used in these tests is approximately 1.9 watts at 17,000 rpm and 2.4 watts at 18,250 rpm. The average rotor velocity coefficients for these output powers are 0.34 for 1.9 watts and 0.53 for 2.4 watts. The increase in rotor velocity coefficient with the new rotor is 1.56 times. I didn't quite get the maximum I thought was possible, but this is a very significant increase. The original rotor has 24 pockets and the new rotor has 48 pockets. In Dr. Balje's study of high energy level, low output turbines the highest average rotor velocity coefficient for a Terry turbine with a single nozzle and 45 blades was 0.53 The open pockets appear to be as efficient as the Terry turbine blades. |
Turbine Guy | 10/04/2019 21:06:52 |
541 forum posts 578 photos | Based on the success of the new rotor that verified the importance of using as many blades or pockets as practical, I’m going to try velocity staging next. I looked at making a Terry turbine with a reversing chamber as shown on the drawing of the 04/03/2019 post. I was able to come up with ways to machine the blades but since the performance of the open pockets appeared to be about the same as with blades, I’m looking at other possibilities. I compared the estimated performance of the Terry turbine with an open pocket design that used two rows of blades on the rotor and an open pocket reversing chamber as shown on the following drawing. Since a new housing is needed, I increased the number of pockets from 48 to 60. I also made the ratio’s of the nozzle admission length (a), reversing chamber admission length (ar), and the rotor pitch length (t) approximately even multiples (a/t = 0.103/.051= 2.02 and ar/t = 0.051/0.051 = 1). With these improvements to the open pocket design, the estimated maximum power was about the same as for the Terry design. The wider blades required for the corkscrew type of flow of the Terry turbine resulted in about 2.5 times the flow length of the open pocket design per stage. Both types allow the flow to expand as it travels, so the length of travel is very important. Dr. Balje’s methods of estimating performance take this into account and were what I used to in my comparison. |
DrDave | 10/04/2019 21:29:34 |
264 forum posts 52 photos | I was wondering how you were going to machine the reversing chamber around the whole internal circumference: I had forgotten that you only need a short length. A very elegant design! I hope that it runs well. |
Martin Johnson 1 | 13/04/2019 09:58:57 |
320 forum posts 1 photos | Turbine Guy, I have just caught up with your post of 14/3/19 doing outline design calculations for a turbine and a turbine / ejector combination. Carefully thought through again, and interesting that it shows things to be roughly the same - i.e. ejector losses balance turbine efficiency gains. Thanks for that. How well do you think the Ds Vs. Ns chart reflects things in your tiny turbines? I will be very interested to see what you get from the two stage open pocket design. - I dare say you will be as well. Thanks for a great thread, Martin |
Turbine Guy | 13/04/2019 18:31:22 |
541 forum posts 578 photos | DrDave, Thanks for your kind remarks. I hope the new turbine meets my expectations. I’ll start turning out the parts when the indexer I ordered arrives.
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Turbine Guy | 18/04/2019 21:56:20 |
541 forum posts 578 photos | I looked at the axial rotor and nozzle that would give the efficiency given in the last post. The rotor and nozzle assumptions used by Dr. Balje in the Ns Ds Diagram are: |
Turbine Guy | 28/04/2019 16:27:23 |
541 forum posts 578 photos | The following picture of my Excel spreadsheet shows how I document the performance from my testing and compare the results with the guidelines given by Dr. Balje. This is the spreadsheet I made for the tangential turbine described in the post of 26/03/2019. I can check the estimated performance with the actual performance using this spreadsheet. The spreadsheet shows the pressures, temperatures, and mass flow of the air used in the test and the estimated and actual performance with these values. The spreadsheet also shows all the applicable turbine dimensions used in the calculations. The spreadsheet includes the estimated velocities of the air at each stage of its passage from the nozzle through the rotor. Fig. IV.24 is the Ns Ds diagram for axial turbines with approximately 40 blades and Fig. IV.42 is the Ns Ds diagram for Terry turbines with approximately 40 blades from Dr. Balje’s report. The Ns Ds diagram shown in the 14/03/2019 post is for axial turbines with approximately 66 blades. |
Werner Jeggli | 12/05/2019 23:09:44 |
28 forum posts 6 photos | Gentlemen, I just hit upon your thread - and I'm very interested. Obviously, you are all professionals and I'm trying to follow your arguments. But I'm confused! You started out with the idea of a steam turbine. But in the later posts, the discussion is based on air turbines - right ? That are totally different kettles of fish. I think that your method of measuring the turbine output is not very accurate. Using a brushless generator gives you shaft power and rpm - see ME Vol.207, No.4412, September 2011 (Dampfsprinter) and ME Vol 215, No.4514 (Turbomotive). There, I also tried to determine turbine efficiency. My latest project, the PRR-S2 is also quite successful (search YouTube under "PRR-S2, Jeggli" At present I'm working on a lost wax cast turbine design, hopefully delivering 10 Watt shaft power at 35'000 rpm.
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Turbine Guy | 13/05/2019 15:01:45 |
541 forum posts 578 photos | Thank you for your post Werner. This thread was intended to share information on model turbine designs for air, steam, or any other medium. In the case of my model turbine it has run on both steam and air. I prefer to do the testing on air since the output of my airbrush compressor is more consistent and it is much easier to set up and run. |
Werner Jeggli | 15/05/2019 20:40:42 |
28 forum posts 6 photos | David Carpenter approached me about an input for his modelengineeringwebsite.com . I sent him details of my past contributions to the SMEE Journal. I hope, David will tell us when they will be online. On my side, I would love to hear about any other successful model steam turbine application - with pictures/videos and performance data if possible.
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Turbine Guy | 15/05/2019 20:54:39 |
541 forum posts 578 photos | Werner, |
Werner Jeggli | 18/05/2019 16:53:08 |
28 forum posts 6 photos | Hello Turbine Guy, Thank you for the flowers. You are right of course with your nozzle proposal, which is in line with the real world technology. The thing is, it doesn't work for my small model turbines. I'm not a watch maker, and with a 0.8mm orifice I'd have problems producing it. Then, in our locos, the space available for nice straight and smooth steam runs is limited. Thirdly (and probably most importantly), the steam leaving the nozzle will be turbulent, creating complete chaos in the turbine housing. This makes nice calculations to the third digit irrelevant! My best results so far I got with doctors injection needles 0.8mm ID and 1.2mm OD, suitably bent and silver soldered in. In the next days, should be receiving improved sets of lost wax cast nozzle units, eliminating the need for injection needles and also new lost wax cast turbine wheels. Well - I'm hopeful. |
Martin Johnson 1 | 18/05/2019 20:27:48 |
320 forum posts 1 photos | If it makes Turbine Guy feel better, my old company that I trained with (W.H. Allen & Co, Bedford - see **LINK**) used to have an air turbine testing rig that was used for developing blading on steam turbines. So there is every good reason for using air as a convenient medium for development purposes. Martin |
Mark Rand | 18/05/2019 23:22:04 |
1505 forum posts 56 photos | Likewise, GEC turbines/Alstom/GE, who paid me money for most of my life, have a model air turbine* in the Aerodynamics labs at Willans Works in Rugby. Due to reorganisation and politics, it's the only meaningful part of the labs left now.
*single stage 1000hp with air provided in a closed loop by the compressor stages of a J57 turbojet, driven by a geared up variable speed electric motor. |
Turbine Guy | 19/05/2019 16:24:25 |
541 forum posts 578 photos | Hi Werner, Thanks Martin and Mark for pointing out that others are using air instead of steam for testing and development. In my case, being able to just push a button and have air at the set pressure immediately available is a big advantage. Edited By Turbine Guy on 19/05/2019 16:26:46 |
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