Armando Meneses | 05/07/2011 12:34:07 |
31 forum posts 2 photos |
I have some doubts in reading the plans. I'm marking the frame, and do not understand certain designations. Along one part of the plan, I hope not be committing any offense by putting only a part of the plan.
what it means:
- 5 ° 05 '
Armando
Edited By Katy Purvis on 01/06/2015 11:47:50 |
Armando Meneses | 05/07/2011 12:36:43 |
31 forum posts 2 photos | The plan did not. You can see in my photos Armando |
Steambuff | 05/07/2011 14:39:16 |
![]() 544 forum posts 8 photos | My best guess is -- C/L Motion is "Center Line" Motion
5 ° 05 ' is 5 Degrees & 5 Minutes (60 Minutes = 1 Degree)
Dave
|
Armando Meneses | 05/07/2011 15:02:02 |
31 forum posts 2 photos | Hello Dave You mean that I have to measure an angle of 5, 083? Is that it? Armando |
Steambuff | 05/07/2011 15:38:16 |
![]() 544 forum posts 8 photos | Yes ... |
JasonB | 05/07/2011 16:43:33 |
![]() 25215 forum posts 3105 photos 1 articles | You may not need to measure the angle, it could just be there as a check. If the position of the cylinder is shown as a distance from the axle and height above it you don't need to measure the angle.
You can also use trig to mark the angle onto the frames, measure say 12" from the axle and 1.226" above it and join this point to teh axle centre line, that will give you your 5 deg 05'.
Jason |
Armando Meneses | 05/07/2011 17:08:14 |
31 forum posts 2 photos | Hello JasonB I appreciate your effort. I really do not think easy to have a measure like this. Measure 5º, ok, measuring 5, 083 is not easy to make acurate. It seems that the way you explain, is easier, but I do not understand by words. If there is any other way, thank you. Armando |
JasonB | 05/07/2011 17:33:27 |
![]() 25215 forum posts 3105 photos 1 articles | I'll post a sketch later |
Armando Meneses | 05/07/2011 17:43:56 |
31 forum posts 2 photos | Ok, JasonB Thanks |
JasonB | 05/07/2011 17:52:01 |
![]() 25215 forum posts 3105 photos 1 articles | Well it always pays to write out your calculations, for a 12" length the rise at 5deg05' will be 1.068" not what I said earlier.
As you can see we know the angle and can choose a length, in this case 12". Using trig we work out the the opposite side to the angle and get 1.068". So rather than use a protractor, angle gauge or similar to mark the angle just measure along the frame 12" and up 1.068" and draw a line through this point and the axle center line. If there is not room for 12 " then use say 6" and 0.534" rise or any pro rata sizes.
Sine plates would be another way but use the same principle of a known distance and a rise that is set by packers to give the angle.
J |
Armando Meneses | 05/07/2011 18:49:42 |
31 forum posts 2 photos | JasonB Thank you. At night after dinner, I see what comes out. Armando |
David Haynes | 05/07/2011 23:48:59 |
168 forum posts 26 photos | Without a doubt, the use of 'large' linear measurements is a far more accurate way of setting an angle than 'small' angular measurements. It may be that the drawing has the angle on for information only, not for setting out.
Dave |
Armando Meneses | 06/07/2011 11:09:29 |
31 forum posts 2 photos | Something is escaping me. Last night I tried to score with measures that gave JasonB, but where it crosses the line with the center point is far from the point that drawing. As I have a protractor to measure and tried in this way is more nearly in point. It was too late and was tired, not to repeat the calculations, I'll try again tonight. JasonB how to get the value 0.088954 and R? Armando |
JasonB | 06/07/2011 16:17:37 |
![]() 25215 forum posts 3105 photos 1 articles | If you enter 5.08333 into a your calculator and then press teh TAN button this will give you 0.88954.
Its my writing thats not an R its 12 eg the 12"
My sketch is not to scale teh angle will be less than I have drawn.
J |
Armando Meneses | 06/07/2011 16:48:34 |
31 forum posts 2 photos | Ok, JasonB Thank you Armando |
Armando Meneses | 07/07/2011 11:36:51 |
31 forum posts 2 photos | Hello Yesterday I went back to try to set the angle. As I said yesterday, last night, was tired and did not realize that this scoring less than 12". Yesterday tried again and it worked properly marked. Thank you. Armando |
Armando Meneses | 22/09/2011 18:57:53 |
31 forum posts 2 photos | Hello. Thank you. Armando. |
JasonB | 22/09/2011 19:06:22 |
![]() 25215 forum posts 3105 photos 1 articles | CRS could be Cold Rolled Steel, can you give us a bit more information about the part.
But more likely to be two points spaced at 10" CentReS, but you have left a space between the 10 and "
PCD Pitch Circle Diameter, this is used to describe a group of holes spaced around a given point, the holes are pladed on a given diameter. So "6 holes on 1" PCD would be six equally spaced holes around a 1" dia circle or 1/2" from the centre point.
J
Edited By JasonB on 22/09/2011 19:09:13 |
Jens Eirik Skogstad | 23/09/2011 00:39:50 |
![]() 400 forum posts 22 photos | Difficult to place the cylinder exactly to the center of wheel shaft by angle. You can check the angle is right: Take a long rod with 2 slices that fit exactly in the center of cylinder bore and adjust the cylinder to the rod is positioned over the axle center before you notice the mounting holes should be on the frame. The rod acts as a center line between the cylinder and shaft. |
JasonB | 23/09/2011 07:25:27 |
![]() 25215 forum posts 3105 photos 1 articles | Posted by Jens Eirik Skogstad on 23/09/2011 00:39:50:
Difficult to place the cylinder exactly to the center of wheel shaft by angle. You can check the angle is right: Take a long rod with 2 slices that fit exactly in the center of cylinder bore and adjust the cylinder to the rod is positioned over the axle center before you notice the mounting holes should be on the frame. The rod acts as a center line between the cylinder and shaft. Yes but he needs to establish the angle first otherwise just jusing a rod you could have the cyl lined up anywhere around a 360deg radius.
Your method is really only to ensure that the axis of the cylinder is in line with the 5deg angle.
Anyway the cylinder is hopefully on by now as that part of the question was asked a few months ago
J Edited By JasonB on 23/09/2011 07:26:23 |
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