Member postings for Mike Wood 1

Hi, and thanks very much for all your helpful advice.

As suggested, I've had a quick go at attacking it (fairly gently - it looks pretty old) with an ohmmeter to see if I could add anything in the way of useful information.

I first disconnected the black wire and red wire that you can see coming from underneath the terminal plate to terminals A1 and A2.

Measuring the resistance from the free end of the black wire to the free end of the red one gave me a reading of 6.2 ohms.

The resistance between terminals A1 and A2 was now 15.8 ohms.

Neither terminal T2 nor T3 seemed to be connected to anything else - they were both open circuit to A1, A2 and each other.

cheers

Mike

Hi, I've recently rescued a slightly beaten-up ML7 (from a cowshed, in Ohakune). There's a motor attached but there's no cable wired in.

The motor's nameplate says it's a single-phase 1/3HP 1425rpm Associated Electrical Industries Ltd one

It looks to have 4 terminals in the terminal block, labelled A1, A2, T2 and T3. I don't see a T1!

There are helpful wiring instructions underneath the wiring cover as well, suggesting the following (not sure the photo's come out all that clearly...)

Connect mains - to A1 & A2, but if overload device fitted - to A1 & T3

Connect capacitor (if fitted) to A1 & T2

To reverse rotation interchange leads from inside motor to A1 & A2

The motor spins if I connect power to A1 & A2 (like it says, although I've only tried it unloaded while it was clamped on the bench). It mentions a capacitor though - would this have been a start capacitor? Possibly missing with the cable or switch etc if it was originally there.

Anyway, I wondered if anyone was familiar with these motors, and...

- if it's ok to use the motor on the lathe as-is, just connecting mains from my switch to A1 & A2 (or is it likely to need a capacitor)?

- if it needs a capacitor, is there a ballpark size for a motor like this? Hunting on google brought me to a rule-of-thumb calculation of

Cap size (uF) = (2650 x Full load amps ) divided by supply Voltage, which comes out to about 28uF for me -- (2650 x 2.5) / 240

thanks for any advice anyway